Linear Functions and Applications
Linear function: a function that has constant rate of change (regardless of which 2 points are
used to calculate it). It increases (or decreases) at the same rate (over specified interval of x).
Cost function: If the cost of producing x items is linear (i.e. it increases by the same amount
regardless of how many items are produced), then we can write the equation:
C(x) = mx + b
m – marginal cost (rate of change of cost at the level of production of x items). If cost is a linear
function, then m is the slope. Marginal cost is also defined as increase/decrease in cost for next
item or cost of producing one additional item (i.e. if we know marginal cost at a level of 100
items, it approximates the cost for producing 101st item).
b – fixed cost. Typically this means initial (upfront) cost or any costs that are constant (over
specified period of time) such as rent, utilities, etc.
Revenue function: The revenue R(x) from selling x units is the product of price per unit p and
the number of units sold (demand) x.
R(x) = p x
Break-even quantity: The number of units x for which the revenue equals (matches) the cost
i.e. x such that R(x) = C(x).
Break-even point: Corresponding ordered pair (point) for break-even quantity x.
Profit: Difference between revenue R(x) (gross amount) and cost C(x).
P(x) = R(x) – C(x)
1. Write a linear cost function. Identify all variables used.
a) Lake Tahoe resort charges a snowboard rental fee of $10 plus $2.25 per hour.x – number of hours for a rental
C(x) = 2.25x + 10
b) A parking garage charges 2 dollars plus 75 cents per half-hour.
x – number of half-hours
C(x) = 2 + .75x
2. Assume each situation can be expressed as a linear cost function. Find the cost function in
each case.
a) Fixed cost: $100; 50 items cost $1600 to produce.
We need to find slope. We have 2 points: (0, 100) and (50, 1600).
m =1600-100 / 50-0= 30
C(x) = 30x + 100
b) Marginal cost: $75; 50 items cost $4300 to produce.
In this case, we have slope but we must either find b or use point-slope equation: y – y1 = m(x –
x1)
m = 75
y – 4300 = 75(x – 50)
y = 75x + 550
C(x) = 75x + 5503) T-shirt cost Joanne Wendel sells t-shirts at community festivals and fairs. Her marginal cost to
produce one t-shirt is $3.50. Her total cost to produce 60 t-shirts is $300, and she sells them for
$9 each.
a) Find the linear cost for Joanne’s t-shirt production.
C(x) = 3.50x + 90 How did I obtain this result?
b) How many t-shirts must she produce and sell in order to break even?
R(x) = 9x
R(x) = C(x)
9x = 3.50x + 90
5.50x = 90
x = 16.36
x = 17 t-shirts (we round up in this case since this is the smallest number of t-shirts that Joanne
must sell in order to break-even (match her cost)).
c) How many t-shirts must she produce and sell in order to make a profit of $500?
P(x) = R(x) – C(x) = 9x – (3.50x + 90) = 5.50x – 90 = 500
x = 107.27 ≈ 108 t-shirts
Supply and demand
q – quantity produced or sold
p – price per unit
Demand: D(q) is based on the principle that demand decreases as price increases.
Supply: S(q) increases as price increases.We will use q as independent variable (x) and p as dependent (y): (q, p)
i.e. p = D(q) and p = S(q)
Equations for D(q) and S(q) are different but same variables are used.
Equilibrium quantity: q such that D(q) = S(q)
Equilibrium price: p = D(q) = S(q)
Surplus: demand < supply (D(q) < S(q)), which makes sense as quantity supplied exceeds the
quantity demanded.
Shortage: demand > supply (D(q) > S(q)) as the quantity demanded exceeds the quantity
supplied.
1) Suppose the demand and price for a certain model of wristwatch is
p = D(q) = 16 – 1.25q
where p is price (in dollars) and q is the quantity demanded (in hundreds).
a) Find the price at each level of demand.
1) 0 watches
2) 400 watches
1) q = 0
p = D(0) = $16
2) q = 4
p = D(4) = $11b) Find the quantity demanded for the watch at each price.
1) $8
2) $10
1) p = D(q) = 16 – 1.25q = 8
q = 6.4 hundred watches = 640 watches
2) 16 – 1.25q = 10
Q = 4.8 hundred watches = 480 watches
Suppose the price and supply of the watch is defined by
P = S(q) = 0.75q
where p is price (in dollars) and q is quantity supplied (in hundreds)
c) Find the quantity supplied for each price.
1) $0
2) $10
1) 0.75q = 0
q = 0 watches
2) 0.75q = 10
q = 13.33 hundred watches = 1333 watches
d) Find equilibrium quantity and price.
D(q) = S(q)
16 – 1.25q = 0.75q
16 = 2q
q = 8 hundred watches = 800 watches
p = 0.75 (8) = $6 Note: you can plug into D(q) or S(q) since both are equal.Linear Functions and Applications
Linear function: a function that has constant rate of change (regardless of which 2 points are
used to calculate it). It increases (or decreases) at the same rate (over specified interval of x).
Cost function: If the cost of producing x items is linear (i.e. it increases by the same amount
regardless of how many items are produced), then we can write the equation:
C(x) = mx + b
m – marginal cost (rate of change of cost at the level of production of x items). If cost is a linear
function, then m is the slope. Marginal cost is also defined as increase/decrease in cost for next
item or cost of producing one additional item (i.e. if we know marginal cost at a level of 100
items, it approximates the cost for producing 101st item).
b – fixed cost. Typically this means initial (upfront) cost or any costs that are constant (over
specified period of time) such as rent, utilities, etc.
Revenue function: The revenue R(x) from selling x units is the product of price per unit p and
the number of units sold (demand) x.
R(x) = p x
Break-even quantity: The number of units x for which the revenue equals (matches) the cost
i.e. x such that R(x) = C(x).
Break-even point: Corresponding ordered pair (point) for break-even quantity x.
Profit: Difference between revenue R(x) (gross amount) and cost C(x).
P(x) = R(x) – C(x)
1. Write a linear cost function. Identify all variables used.
a) Lake Tahoe resort charges a snowboard rental fee of $10 plus $2.25 per hour.x – number of hours for a rental
C(x) = 2.25x + 10
b) A parking garage charges 2 dollars plus 75 cents per half-hour.
x – number of half-hours
C(x) = 2 + .75x
2. Assume each situation can be expressed as a linear cost function. Find the cost function in
each case.
a) Fixed cost: $100; 50 items cost $1600 to produce.
We need to find slope. We have 2 points: (0, 100) and (50, 1600).
m =
= 30
C(x) = 30x + 100
b) Marginal cost: $75; 50 items cost $4300 to produce.
In this case, we have slope but we must either find b or use point-slope equation: y – y1 = m(x –
x1)
m = 75
y – 4300 = 75(x – 50)
y = 75x + 550
C(x) = 75x + 5503) T-shirt cost Joanne Wendel sells t-shirts at community festivals and fairs. Her marginal cost to
produce one t-shirt is $3.50. Her total cost to produce 60 t-shirts is $300, and she sells them for
$9 each.
a) Find the linear cost for Joanne’s t-shirt production.
C(x) = 3.50x + 90 How did I obtain this result?
b) How many t-shirts must she produce and sell in order to break even?
R(x) = 9x
R(x) = C(x)
9x = 3.50x + 90
5.50x = 90
x = 16.36
x = 17 t-shirts (we round up in this case since this is the smallest number of t-shirts that Joanne
must sell in order to break-even (match her cost)).
c) How many t-shirts must she produce and sell in order to make a profit of $500?
P(x) = R(x) – C(x) = 9x – (3.50x + 90) = 5.50x – 90 = 500
x = 107.27 ≈ 108 t-shirts
Supply and demand
q – quantity produced or sold
p – price per unit
Demand: D(q) is based on the principle that demand decreases as price increases.
Supply: S(q) increases as price increases.We will use q as independent variable (x) and p as dependent (y): (q, p)
i.e. p = D(q) and p = S(q)
Equations for D(q) and S(q) are different but same variables are used.
Equilibrium quantity: q such that D(q) = S(q)
Equilibrium price: p = D(q) = S(q)
Surplus: demand < supply (D(q) < S(q)), which makes sense as quantity supplied exceeds the
quantity demanded.
Shortage: demand > supply (D(q) > S(q)) as the quantity demanded exceeds the quantity
supplied.
1) Suppose the demand and price for a certain model of wristwatch is
p = D(q) = 16 – 1.25q
where p is price (in dollars) and q is the quantity demanded (in hundreds).
a) Find the price at each level of demand.
1) 0 watches
2) 400 watches
1) q = 0
p = D(0) = $16
2) q = 4
p = D(4) = $11b) Find the quantity demanded for the watch at each price.
1) $8
2) $10
1) p = D(q) = 16 – 1.25q = 8
q = 6.4 hundred watches = 640 watches
2) 16 – 1.25q = 10
Q = 4.8 hundred watches = 480 watches
Suppose the price and supply of the watch is defined by
P = S(q) = 0.75q
where p is price (in dollars) and q is quantity supplied (in hundreds)
c) Find the quantity supplied for each price.
1) $0
2) $10
1) 0.75q = 0
q = 0 watches
2) 0.75q = 10
q = 13.33 hundred watches = 1333 watches
d) Find equilibrium quantity and price.
D(q) = S(q)
16 – 1.25q = 0.75q
16 = 2q
q = 8 hundred watches = 800 watches
p = 0.75 (8) = $6 Note: you can plug into D(q) or S(q) since both are equal.
